The temperature of a sample of Br2 is changed without changing its volume, causing a change in pressure from 602.12 kPa to 762.15 kPa. If the starting temperature was 449.46 K, what is the final temp

Question

The temperature of a sample of Br₂ is changed without changing its volume, causing a change in pressure from 602.12 kPa to 762.15 kPa. If the starting temperature was 449.46 K, what is the final temperature in kelvins?

Answer 1

Hello, Brandy,

Use the P1V1/T1 = P2V2/T2 equation I described in an earlier answer, Rearrange it to isolate T2, the unknown in this case.

T2 = T1(V2/V1)(P2/P1)

Enter the data and solve. I think the temperature will go up, to around 569K

Bob