help please Use the following reaction: Zn + 2HCl -> ZnCl2 + H2

Question

If 5.0 moles of HCl reacts with an excess amount of Zn, how many moles of ZnCl2 are produced?

Answer 1

Hello, Jaccari,

The balanced equation tells us that 1 mole of Zn reacts with 2 moles of HCl to form 1 mole each of ZnCl₂ and H₂. We can state that

(1 mole ZnCl₂)/(2 moles HCl)

Since we have excess zinc, we can assume all 5 moles of HCl are consumed, Now we can use the conversion factor above:

[(1 mole ZnCl₂)/(2 moles HCl)]*[(6 moles HCl)] = 3 moles ZnCl₂

Bob