Use the following reaction: N2 + 3H2 -> 2NH3

Question

How many moles of NH3 is produced if 25.0 g of N2 is reacted with an excess of H2?

Answer 1

Stoichiometric ratio( mole ratio) from the balanced equation = 2 moles NH3

1 mole N2

Convert the grams of N₂ in to moles, and multiply by the stoichiometric ratio as follows—

25.0 g N₂ x 1 mole N₂ x 2 moles NH₃ = 2.93 moles of NH₃ produced

17.04 g 1 mole N2

[ 17.04 g is the molar mass of NH₃]