How many moles of Cl2 are required to react with 4.96 g of KMnO4? Show work please

Question

Answer the question based on the reaction of potassium permanganate with hydrochloric acid.

2 KMnO₄ + 16 HCl → 5 Cl₂ + 2 KCl + 2 MnCl₂ + 8 H₂O

How many moles of Cl₂ are required to react with 4.96 g of KMnO₄?

Report value to 2 dec. points

Answer 1

4.96 g KMnO₄ 1 mol KMnO₄ 5 moles Cl₂ 70. 9 grams = 5.56 grams

158 grams 2 moles KMnO₄ 1 moles Cl₂