Taylor M.
asked 03/18/21
Stoichiometry hw help!
Answer the question based on the reaction of potassium permanganate with hydrochloric acid.
2 KMnO4 + 16 HCl → 5 Cl2 + 2 KCl + 2 MnCl2 + 8 H2O
How many grams of water will be produced when 427 g of KMnO4 react?
Report value to 1 dec. point
Sidney P.
answered 03/19/21
Astronomy, Physics, Chemistry, and Math Tutor
The stoichiometry is 427g KMnO4 * (1 mol KMnO4 / 158.0g KMnO4) * (8 mol H2O / 2 mol KMnO4) * (18.02g H2O / 1 mol H2O) = 194.8g H2O.
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