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Question

Find sin(x−2π​) if cosx=0.65.

Answer 1

sin(x - 2π) = sinxcos(2π) - cosxsin(2π) = sinx

Since cos²x + sin²x = sin²x = 1 - cos²x. So, sinx = ±√ [1 - cos²x]

Assuming that x is acute, sinx = √ [1 - cos²x ] = √ [1 - (0.65)²] = 0.76