
Sidney P. answered 03/19/21
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The stoichiometry is (2.40 mol H2)*(2 mol NH3 /3 mol H2)*(17.0g NH3 /1 mol NH3) = 27.2g NH3.
Muhammad N.
asked 03/18/21For the reaction
3 H2 (g) + N2 (g) → 2 NH3 (g),
how many grams of ammonia will be produced from 2.40 moles of hydrogen gas?
Sidney P. answered 03/19/21
Astronomy, Physics, Chemistry, and Math Tutor
The stoichiometry is (2.40 mol H2)*(2 mol NH3 /3 mol H2)*(17.0g NH3 /1 mol NH3) = 27.2g NH3.
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