Sidney P. answered • 03/19/21
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Apparently the temperature is constant, so the ideal gas law simplifies to P1V1 = P2V2, and 62.966 P1 = (7.6033)*(16.107). This gives P1 = 1.9450 atm.
Sidney P.
At fixed volume, P1/P2 = T1/T2, P1 = P2*T1/T2 = 1661.0 kPa
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03/19/21
BRANDY E.
Thank you! Can you help me with this one? A sample of C2H6 in a rigid container has its temperature changed from 455.07 K to 223 K. If its new pressure is 813.95 kPa, what was its initial pressure in kilopascals?03/19/21