How many particles of Ne are present in 537 L of Ne?

Answer 1

Assuming this is a gas at STP,

Standard molar volume:

1 mol gas at STP = 22.4 L

So, convert 537 L to mol:

mol= ^537L/₁ × ^1mol/_22.4L = 23.973214 mol

Convert moles to particles (particles will be atoms because Ne is an element)

1 mol Ne = 6.02×10²³ atoms Ne

atoms Ne= ^23.973214mol/₁ × ^{6.02×10^23 atoms Ne}/_{1 mol Ne} =1.44×10²⁵ atoms Ne