Corban E. answered 03/18/21
AP Chemistry Tutor and Former Teacher (Gen Chem, IB, O-Level, A-Level)
% composition of C12H22O11
molar mass C12H22O11 = 12C+22H+11Oxygen
molar mass=12(12.01)+22(1.01)+11(16.00)=342.34 g/mol
%C=(mass 12 atoms C / mass C12H22O11)100
%C=(12*12.01/342.34)100
=42.1%
%H=(mass 22 H atoms / mass C12H22O11)100
%H=(22*1.01/342.34)100
=6.49%
%O=100-%C-%H
%O=100-42.1-6.49
=51.4%