How many grams of iron(iii) sulfate are produced when 0.23 moles of iron(iii) oxide is reacted with an excess of sulfuric acid

Answer 1

Write the balanced equation:

Fe₂O₃+3H₂SO₄→Fe₂(SO₄)₃+3H₂O

Convert moles to moles using the coefficients from the balanced equation:

(0.23 mol Fe₂O₃ / 1) × (1 mol Fe₂(SO₄)₃/ 1 mol Fe₂O₃) = 0.23 mol Fe₂(SO₄)₃

Convert moles to grams using the molar mass:

(0.23 mol Fe₂(SO₄)₃ / 1) × (399.88 g Fe₂(SO₄)₃ / 1 mol Fe₂(SO₄)₃) =91.9724=92 g Fe₂(SO₄)₃