The kw for water is 5.5 x 10-14 at 50oC. What is the pH of a neutral aqueous solution at 50oC?

Answer 1

Since the solution is neutral , [H+] = [OH-] and since the product of the concentrations is 5.5 x 10^-14 ,

both concentrations are sqrt(5.5 x 10^-14 )

= 2.345 x 10 ^-7

Then pH = - log(2.345 x 10^-7 ) = 6.63