First you need the balanced equation:
2 AlCl3 → 2 Al + 3 Cl2
(70.90 g Cl2/1 mol Cl2) (3 mol Cl2/2 mol AlCl3) (10.00 mol AlCl3) = 1064 g Cl2
Arshi P.
asked 03/17/21531.8 grams Cl2
1,064 grams Cl2
1,595 grams Cl2
2,127 grams Cl2
First you need the balanced equation:
2 AlCl3 → 2 Al + 3 Cl2
(70.90 g Cl2/1 mol Cl2) (3 mol Cl2/2 mol AlCl3) (10.00 mol AlCl3) = 1064 g Cl2
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