A student conducted an experiment, and calculated that the theoretical yield for carbon dioxide is 2.5 moles. The actual yield was 44 grams of carbon dioxide.

Question

HC2H3O2 + NaHCO3 ⟶ H2O + CO2 + NaC2H3O2

What is the percent yield for carbon dioxide?\

show all work please

Answer 1

So here is the answer

% Yield =. Actual Yield/Theoretical Yield. x 100

Actual yield =. 44 grams

Theoretical yield = 2.5 moles ( We need to convert it into grams because our actual yield is in grams)

So to convert moles of CO2 into grams we need the molar mass of CO2, which is 44.01 grams (Mass of 1 mole of CO2)

now we can convert moles of CO2 into grams of CO2 as below

2.5 moles CO2. x 44.01 g = 110.03 g (Theoretical yield in grams)

1 mole CO2

Now plug in the actual yield and Th.yield into the formula. % yield =. Actual Yield. x 100

Theoretical Yield

= 44 g x 100 = 39.99 %

110.03 g

And always we need to watch for the sig figs in our answers ( I do not think the # 44 g for actual yield that you provided is the complete #, so check that in your original question)