
Stanton D. answered 03/17/21
Tutor to Pique Your Sciences Interest
Hi snigdh K.,
Well, you have a lot of implied calculations packed in there. The total acceleration isn't zero; the car follows the curve, so it is accelerating (the direction of velocity is changing). You calculate that for the "circular" equivalent path, don't you. If there weren't that static friction (well, that's hedging the squirm of the tire a bit!), the car would continue straight and plunge off the road. And by the way, the best motorcycle racers can drift both tires on a curve, that's in between static and dynamic friction, perhaps. -- Cheers, --Mr. d.
Snigdh K.
i am sorry but i still dont get it, the book says that the force that causes the acceleration needed for travelling the circular path is static friction. But to cause that static friction we need to first apply a force, and only then will an equal and opposite magnitude static friction be created . Then wouldnt the force applied on body be 0 if the causing factor is only static friction due to the cause required for that static friction. I would like to send u a free body diagram, could you please give me your email or something?03/17/21