Sidney P. answered 03/18/21
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The balanced reaction is 2 NaNO3 --> 2NaNO2 + O2.
The stoichiometry is (32.8g O2) * (1 mol O2 / 32.0g O2) * (2 mol NaNO2 / 1 mol O2) * (85.0g NaNO2 / 1 mol NaNO2) = 174g NaNO2.
Rita P.
Thank you!03/18/21