How many moles of NaCl (sodium chloride) will be produced from 71 grams of Cl2 (chlorine gas)? The balanced equation being: 2Na + Cl₂ → 2NaCl

Answer 1

The stoichiometry is (71g Cl₂) (1 mol Cl₂ / 70.9g Cl₂) (2 mol NaCl / 1 mol Cl₂) = 2.003 mol NaCl. (The latter term comes from the mole ratio in the balanced reaction)