chemistry help please

Question

The temperature of a sample of fluorine gas is changed without changing its volume, causing a change in pressure from 46.0 kPa to 129.0 kPa. If the starting temperature was 225 °C, what is the final temperature in degrees Celsius?

Answer value

Answer 1

So here the volume is constant , P & T are changing, So we need to apply the Pressure-Temperature Law here ( P1/T1 =. P2/T2)

P1 = 46.0 kPa (given

P2 =. 129.0 kPa (given)

T1. = 225 °C. ( 498 K — Always convert temp to Kelvin when using gas laws)

T2. =. ?

plug in these #s in the formula below to solve for T2

P1/T1 =. P2/T2. Switch to solve for T2. we get. T2. =. P2 . T1. =. 129.0 kPa x. 498 K. = 1397 K. = 1120 °C

P1. 46.0 kPa.

Answer 2

From ideal gas law, P₁ V₁ /(P₂ V₂) = n R T₁ /(n R T₂), yielding T₂ = T₁ P₂ /P₁ because V is constant as well as n and R. Convert from °C to K: T₁ = 225 + 273.15 = 498.15.

Then T₂ = (498.15)(129.0) / (46.0) = 1397 K. Convert back to Celsius: T₂ = 1124 °C.