Hello, Cole,
The (ClO) group has a -1 charge, since sodium is +1. SO4 has a -2 charge, so it has 2 hydrogens. The reaction involves the Na and H groups swapping places, to produce Na2SO4 and HClO2.
One needs to choose a place to start when balancing equations. I find the best place is to pick the most complex compound. It's hard to pick in this case, but I'll pick H2SO4, since it has 2 H atoms that need to be accounted for.
Using a pencil, give the H2SO4 a coefficient of 1. That provides two H and 1 (SO4) group. Look at the products and see if we can find homes for the single (SO4) and 2 H's. The Na2(SO4) will take 1 SO4 group, so pencil a 1 for it's coefficient. The only product with H is HClO2. This means the we need 2 of them to accept the 2 hydrogens coming in. Pencil a 2 for it's coefficient (HClO2). So far, so good.
The 1 Na2(SO4) molecule has 2 Na's. The only place we can find sodium is the NaClO2. We'll need to put a 2 for the NaClO2 coefficient.
We'll got coefficents for all the compounds, so now check to see if everything balances. I believe they do, but in most cases it is necessary to erase an initial coefficient and update it. That's why I suggest pencil.
I hope this helps,
Bob