While on vacation, you visit a cave. you shout at a far wall and the sound returns after 6 seconds. The speed of sound that day was 345m/s.

Question

How far was it to the far side of the cave? (The frequency of the sound you made had a frequency of 600 Hz. )

What was its wavelength?

What was its period?

Answer 1

The distance traveled is 2d where d is the distance to the wall. Thus d=345*6/2= 1035 m. a)

b)The frequency is 600 Hz thus the period T = 1/f= 1.67ms

c) The wavelength λ = Velocity/Frequency = 345/600= .575 meters