What is the molarity of a solution made from 17 of lithium iodide in a solution with 3870 mL?

Answer 1

Hi Camila:

Did you mean 17 g of lithium iodide? If so, then the answer is below.

Molarity = # moles or M = n

# L of solution V (in Liters)

To find n, we must first find the molar mass of LiI

From the Periodic Table, the molar masses of Li and I are

Li = 6.94 g

I = 126.9g

Molar mass of LiI = 6.94g + 126.9g = 133.84 g

n = 17g x 1 mole = 0.1278 moles

133.84g

V (in L) = 3870/1000 = 3.87 L

M = n = 0.1278 moles = 0.033 moles or 0.033 M

V 3.87 L L

Answer = 0.033 M