A person has a volume of 0.0743 m3. How much buoyant force does the air exert on him?

Answer 1

This is an application of Archimedes principle. The buoyant force on an object is equal to the weight of the fluid displaced. The fluid in this case is air.

To find the weight of the air displaced, we have to utilize the formula mass = Density x volume and multiply the results by the acceleration of gravity.

weight of air displaced = 1.225 kg/m³ x 0.0743 m₃ x 9.8 m/s² = 0.892 N which is the buoyant force exerted on the person.

Answer 2

F = DVg = 0.0743m³·1.29kg/m³·9.81m/s² = 0.94 N