An 800 g aluminum block cools from 70°c to 25°c. Given that the specific heat capacity of aluminum is 0.902 j/g °c, calculate the heat released.

Answer 1

(Heat)=(mass)(specific heat)(change in temp)

(Heat)=(mass)(specific heat)((Final Temp)-(Initial temp))

q=(m)(C)(ΔT)

here, you are solving for Heat (q)

q = (800g)(0.902 J/g°C)(25°C - 70°C)

q = (800g)(0.902 J/g°C)(-45°C)

q = (721.6 J/°C)(-45°C)

q = (-32,472 J)