How many milliliters of 1.50 M H2SO4 are needed to neutralize 50.0 g of NaOH?

Answer 1

NaOH and Sulfuric acid react with each other in a 2:1 ratio.

50 g of NaOH 1 mole NaOH

40 grams NaOH

1.25 moles NaOH that means moles of Sulfuric acid are 1.25/2

Molarity = moles/liters

1.5 = 0.625 moles/liters Liters = 0.625/1.5 = 0.417 liters