H2SO4 + 2 LiOH → Li2SO4 + 2 HOH
(1 L H2SO4/6.24 mol H2SO4) (1 mol H2SO4/2 mol LiOH) (9.00 mol LiOH/1 L LiOH) (0.6234 L LiOH) = 0.4496 = 0.450 L H2SO4
Molly M.
asked • 03/05/21chem question help please
How many liters of 6.24 M sulfuric acid are requried to fully neutralize 623.4 mL of 9.00 M lithium hydroxide?
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