Calculate the moles of Sodium chloride required to prepare a solution of molarity 4 and volume 0.5 liters that is 2 moles.
Multiply the number of moles with the molar mass of Sodium chloride which is approximately 58.5 g/mo.''
Then your answer is 117 grams.
Molarity = moles/liters
Moles = Molarity X liters
2 moles of NaCl 58.5 grams NaCl
1 mole NaCl