When bismuth reacts with fluorine, bismuth (III) fluoride is produced. If 5.00 g of bismuth reacts with excess fluorine to produce 4.00 g of BiF₃, what is the percent yield?

Answer 1

Bisumuth has a molar mass of approximately 209 g/mol. BiF₃ has a molar mass of approximately 266 g/mol. The 5 g of Bi that was reacted corresponds to 0.0239 moles of Bi (5 / 209) and the product was 0.015 moles (4 / 266). Therefore, the percent yield is 0.015 / 0.0239 * 100 = 62.8%.