chem help please

Question

In a titration, 485.6 mL of a 3.68 M solution of hydrochloric acid is neutralized by with 0.349 L of magnesium hydroxide. What is the molarity of the base?

Answer 1

Multiply the volume of HCl in liters with its molarity to get the moles of HCl ( Molarity= moles/liters),

0.4856 liters * 3.68 = 1.79 moles of HCl

HCl and Magnesium hydroxide react with each other in 2:1 ratio

1.79 mol HCl 1 mol Magnesium hydroxide

2 moles HCl

That gives the moles of Magnesium hydroxide as 0.894 , you already know the volume of the solution as0.349 liters . In order to get the molarity divide the number of moles by the volume which gives the molarity as 2.56 M