Hello, Elie55,
The balanced equation tells us that we'll get 2 moles of silver (Ag) for every one mole of Ag2O, a molar rationof 2:1. We ca n calculate the moles of Ag2O by dividing the mass by it's molar mass. We start with 0.0100 moles of Ag2O, so we would expect to get twice that many moles of Ag, according to the equation. Ha - it assumes we have an honest lab partner.
Multiply the moles of Ag by it's molar mass to get grams Ag, which I find to be 0.980 grams, if everything went accrding the theory.
Since we only got 0.980 grams of Ag, we have a (0.980/1.260)x100% = 45.4% yield.
Bummer,
Bob