Matthew H. answered 03/02/15
Tutor
New to Wyzant
Math - Algebra to Calculus: Middle and high school, some college.
Recall that the area formula of a triangle is:
A = bh/2 ("base times height divided by two")
Since you know the area, you may substitute it in place of A at any time, however that still leaves two unknowns, b and h. The good news is that you know their relationship to each other, which you can write as an equation.
"the base of the triangle is 1 foot longer than the height" translates to:
b = h + 1
Making that substitution into the area formula yields:
A = (h+1)h/2
Distributing the h gives:
A = (h^2 + h)/2
Substitute the known area:
10 = (h^2 + h)/2
Multiply both sides by two to clear out the fraction on the right and use the symmetric property to flip the equation:
h^2 + h = 20
Subtract 20 from both sides and you have the quadratic:
h^2 + h - 20 = 0
Which is factorable. Since the leading coefficient on h^2 is 1, we just need two numbers that multiply to the constant, -20, but add up to the middle coefficient (the one on h), which is 1. These are -4 and 5.
Therefore h^2 + h - 20 = (h + 5)(h - 4) = 0
This gives us the following solutions for h:
h + 5 = 0 -> h = -5
h - 4 = 0 -> h = 4
Since we cannot have a negative number for the height of a triangle, we discard h = -5.
Now returning to our equation that expresses the base in terms of height:
b = h + 1
b = 4 + 1
b = 5
The triangle has a base of 5ft and a height of 4ft.