**45ยข**

one lady finger and six cookies cost $3.05. At the same prices, two lady fingers and four cookies cost $2.50. How much does one cookie cost?

Tutors, sign in to answer this question.

Let F be the cost of one lady finger

Let C be the cost of on cookie.

so,

F + 6C = 3.05 eq. 1

2F + 4C = 2.50 eq. 2

use eq. 1 to solve for F:

F = 3.05 - 6C eq. 3

subsitute eq. 3 to eq. 2

2(3.05 - 6C) + 4C = 2.50

6.10 - 12C + 4C = 2.50

6.10 - 8C = 2.50

6.10 - 2.50 = 8C

3.60 = 8C

so C = $.45

so, each cookie costs **45ยข**

Hey Darlene!

"cut in half" idea: one LF and two C costs $1.25 ... 4 less cookies saves $1.80

"halving tool" again => 4C is 1.80 ... 2C is 0.90 ... **one cookie is 45 cents** ... Regards :)

First, set up an algebraic equation:

lady finger = x

cookie = y

x+6y=3.05

2x+4y=2.50

Then, solve for one variable...

x=3.05-6y

Then, plug in your new equation into the other equation...

2(3.05-6y)+4y=2.50

6.1-12y+4y=2.5

3.6=8y

y= 0.45

Since Y is the price of a cookie, the price of a cookie is 45 cents/$0.45.

Already have an account? Log in

By signing up, I agree to Wyzant’s terms of use and privacy policy.

Or

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Your Facebook email address is associated with a Wyzant tutor account. Please use a different email address to create a new student account.

Good news! It looks like you already have an account registered with the email address **you provided**.

It looks like this is your first time here. Welcome!

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Please try again, our system had a problem processing your request.