math word problem

120t - .75 = 110t

120t - 110t = .75

10t = .75

divide both sides by 10:

t = .075 hours

.075 * 120 = 9 miles

since 1 lap is 3/4 mile, so, 9 miles divided by .75 mile per lap is

**12 laps**.math word problem

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Chicago, IL

120t - .75 = 110t

120t - 110t = .75

10t = .75

divide both sides by 10:

t = .075 hours

.075 * 120 = 9 miles

since 1 lap is 3/4 mile, so, 9 miles divided by .75 mile per lap is **
12 laps**.

Blacksburg, VA

Hey Rosemary -- here's the "play-by-play": PRETEND "A" is 1 mile behind ... at 10 mph closing speed, one mile needs 1/10 of an hour to close ... 120 mph covers 240 "half-miles"/hr OR 480 "qtr-miles"/hr ... three (3) of these "qtr-miles" would be covered 160 times/hr ... 1/10 of an hr travels 16 laps when 1 mile behind ==> the 3/4 mile lag would take 12 laps to catch up ... Best wishes, ma'am :)

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