Redox reactions

Question

(Cr₂O₇₎^2- + 2Al + 14H⁺ <—> 2Cr³⁺ + 2Al³⁺+ 7H₂O

1) how many ml of solution 1.50 M e (Cr2O7)2- are needed to act without residue with 0.8 grams of Al?

2) what is the concentration of the solution (Cr₂O₇₎^2-

Answer 1

0.8 g of Al 1mole Al 1mol Cr₂O₇^2-

26,98 g of Al 2 mol Al

Solving this equation gives you 0.015 moles of Cr₂0₇ ^2-

Molarity = moles/liters

1.5 = 0.015 moles/liters

0.01 liters or 10 ml