When 1 mol of CS2(l) forms from its elements at 1 atm and 25°C, 89.7 kJ is absorbed, and it takes 27.7 kJ to vaporize 1 mol of the liquid. How much heat is absorbed when 1 mol of CS2(g) forms from...

Question

its elements at these conditions? Do not answer in scientific notation.

I got 1174 kJ but it is wrong.

Answer 1

C(s) + 2S ==> CS₂(l)

∆H_f CS₂(g) = -89.7 kJ/mol

∆H_vap CS2(l) = 27.7 kJ/mol

-89.7 kJ/mol - (-27.7 kJ/mol) = 117.4 kJ = 117 kJ (3 sig. figs.)