Dawson H.

asked • 03/02/21

Copper(I) oxide can be oxidized to copper(II) oxide: Cu2O(s) + 1/2 O2(g) → 2 CuO(s).....

ΔH0rxn = -146.0 kJ

Given ΔH0f of Cu2O(s) = −168.6 kJ/mol, find ΔH0f of CuO(s)


1 Expert Answer

By:

Dawson H.

It says that's wrong
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03/03/21

J.R. S.

tutor
The process is correct. Check the math and the significant figures. It doesn't do anyone any good to simply reply "it says that's wrong" without at least trying to figure out why it may be incorrect.
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03/03/21

Dawson H.

I see it. Thank you. It's supposed to be negative which makes sense. Thank you!
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03/03/21

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