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Question

When 293g of AgNO₃ are dissolved in water to form a 0.500-M solution, how many liters of solution are formed?

Answer 1

3.45 Liters of the solution is formed.

293 grams of Silver nitrate is approximately 1.724 moles( 293 g/170 g/mol, Molar mass of Silver nitrate is approximately 170 with rounded number).

Then Molarity = Moles/Liters, In order to obtain the liters divide the moles by the molarity

1.724/0.5 = 3.45 Liters