I got reaction one wrong...Calculate the volume (in mL) of CO2 that forms at 213°C and 0.930 atm per gram of NaHCO3 by each of the reaction processes.

Question

A baker uses sodium hydrogen carbonate (baking soda) as the leavening agent in a banana-nut quickbread. The baking soda decomposes according to two possible reactions.

Reaction one is:

2NaHCO_3(s) ----> Na₂CO_3(s) + H₂O_(l) + CO_2(g)

The answer I got was 235 mL

Answer 1

I'm not sure what you mean by you got reaction one wrong, but given the information I guess you want the CO2 given the reaction one that is in the question, and that you have to react 1 gram of NaHCO3.

So, your first step is identifying your plan, You need volume of CO2, but to get it you need the moles of CO2, but to get that based off of the chemical equation, you can only find the moles of NaHCO3.

In the problem you have one gram of NaHCO3 to react, so in order to find the moles, you convert NaHCO3 using the molar mass. 1g * 1mol/84g = 0.012 mol NaHCO3.

Now you have molar mass, use the equation to convert into the moles of CO2. Now you have 0.006 moles of CO2.

Lastly, is finding the volume using the gas law. PV=nRT. Fill out all the variables

0.93*V = 0.006 * 0.082 * 486 *If R= 0.082, remember to convert T into Kelvin

As a result, V = 255 mL

I hope this helps, if I misread the question. Please don't hesitate to correct me.