The sum of the digits of a two-digit number is 6. When the digits are reversed, the number is increased by 18. Find the original number.

Answer 1

T + U = 6

10U + T = 10T + U + 18

9U -9T = 18

U -T = 2

U+T = 6

2U = 8

U = 4

T = 2

the original number is 24

42 = 24 + 18

4+2 = 6