Answer the following:

Question

The sum of three numbers is 16. The sum of twice the first number, 3 times the second number,

and 4 times the third number is 46. The difference between 5 times the first number and the

second number is 31. Find the three numbers.

Answer 1

x+y+z = 16

2x+3y + 4z = 46

5x-y = 31

4x + 4y + 4z = 64

2x + 3y + 4z =46

2x + y = 18

5x -y =31

7x = 49

x = 7

y = 18-14 = 4

7+4 + z = 16

z=5

(x,y,z) = (7,4,5)