The quartic function has zeros at ‐5, ‐2, and 2 (order 2) and its graph passes through the point ( 1, 3). Write the equation of this quartic polynomial in factor form.

Answer 1

(x+5)(x+2)(x-2)^2

3 = (1+5)(1+2)(1-2)^2 = 6(3)(1) = 18? change 18 to 3 by multiplying by 3/18

f(x) = (3/18)(x+5)(x+2)(x-2)^2