Saqibul C. answered 02/24/21
General Chemistry Tutor with 3 years of experience
Molar mass of H2O = 18 g/mol
Molar mass of BeSO4 = ( 9 + 32 + (16 * 4)) g/mol = 105 g/mol
Molar mass of BeSO4.xH2O = (105 + 18x) g/mol
Moles of BeSO4 = mass/molar mass = 24.84/105 = 0.237 mol
Molar mass = mass/moles
105 + 18x = 41.87/0.237
105 + 18x = 176.67
18x = 71.67
x = 3.98 (closest whole number is 4)
x ~ 4
The formula of the hydrate is BeSO4.4H2O