Given 2.28 moles of Cu, how many grams of AgNO 3 can be formed?. Cu + 2 AgNO 3 Cu(NO3) 2 + 2 Ag

Answer 1

Cu + 2AgNO₃ = Cu(NO₃)₂ + 2Ag

1 mole of Cu produces 2 moles of Ag. So, 2.28 moles of Cu produces (2.28 * 2) = 4.56 moles of Ag

molar mass of Ag = 107.868 g/mol

mass of Ag = moles * molar mass = 4.56 * 107.868 = 491.878 g