
Yefim S. answered 03/17/24
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Volume v = π∫-22(4 - x2)2dx = 2π(16x - 8x3/3 + x5/5)02 = 2π(32 - 64/3 + 32/5) = 512π/15
Dalia S.
asked 03/01/15Yefim S. answered 03/17/24
Math Tutor with Experience
Volume v = π∫-22(4 - x2)2dx = 2π(16x - 8x3/3 + x5/5)02 = 2π(32 - 64/3 + 32/5) = 512π/15
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