question in the description

Question

42g/mol C2H6   32g/mol O2 44g/mol CO2 18g/mol H2O

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

193.2 g C2H6 reacts with excess oxygen.

1. What is the theoretical yield of CO2 based on 193.2g C2H6?
2. What is the Percent yield of CO2 for this reaction based on only 380g CO2 being produced for the product calculated in part a?

Answer 1

We need to find the limiting reagent. 2 moles of C₂H₆ will produce 4 moles of CO₂, or 1 mole of ethane (C₂H₆₎ will produce 2 moles of carbon dioxide. 7 moles of oxygen will produce 4 moles of carbon dioxide or 1 mole of oxygen will produce 0.57 moles of carbon dioxide so oxygen is the limiting reagent.. That means with the ratio of oxygen to ethane being 7/2, and we have 6.44 moles of ethane, we have 22.54 moles of oxygen. and with the ratio of oxygen/carbon dioxide being 7/4, we get 12.88 moles of carbon dioxide or 566.72 grams, the theoretical yield.

If we recover 380 grams of carbon dioxide, we 380/566.72 X 100=67.05%.