Saqibul C. answered 02/24/21
General Chemistry Tutor with 3 years of experience
Molar mass of Mn2(CO3)3 = (54.9 * 2) + (3 * (12 + (16 * 3))) = 289.8 g/mol
Number of moles of Mn2(CO3)3 = 5485 mg * 1g/1000mg * 1mol/289.8g = 0.0189 mol
Volume of Mn2(CO3)3 = 14 mL * 1L/1000mL = 0.014L
Concentration of Mn2(CO3)3 = 0.0189mol/0.014L = 1.35M
Molar mass of LiNO3 = 6.9 + 14 + (16 * 3) = 68.9 g/mol
Number of moles of LiNO3 = 0.85 kg * 1000g/1kg * 1mol/68.9g = 12.34 mol
Concentration of LiNO3 = 12.34 mol/3.2 L = 3.86M
Concentration of LiNO3 is higher.