(2.04 M)X(0.891L) = 1.818 mol
(1.818 mol MgSO4) X (120.366 g/mol) = 218.78 g MgSO4
Zoey S.
asked • 02/19/21Chemistry Molarity
How many grams of magnesium sulfate are needed to make .891 liters of a 2.04 M solution?
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