chemistry molarity

Question

what is the molarity of 0.67 L solution made by dissolving 32.4 grams of copper(II) sulfate in water?

Answer 1

Molar mass of CuSO₄ = (63.55 + 32 + (16 * 4)) g/mol = 159.55 g/mol

Moles of CuSO₄ = Mass/molar mass = 32.4/159.55 = 0.203 mol

Concentration = Moles/volume = 0.203/0.67 = 0.303 M