Daniel B. answered 02/17/21
A retired computer professional to teach math, physics
Let
r = 1.82 m be the radius of the flywheel,
m = 687.7 kg be the mass of the flywheel,
I = mr²/2 be the moment of inertia of the flywheel,
ω = 1943 s-1 be angular velocity of the flywheel,
E = Iω²/2 be the energy stored in the flywheel.
a) Substituting:
E = mr²ω²/4 = 687.7 kg × 1.82² m² × 1943² s-2 / 4 = 2149945298.35813 J
b) Let
P = 7374 W be the power drawn from the flywheel,
t (to be computed) be the time the flywheel is to run.
Given that the car draws power P from the flywheel for t seconds till all the energy
of the flywheel is exhausted,
E = Pt
t = E/P = 2149945298.35813 J / 7374 W = 291557.53978276 s
(That is about 80 hours)