Edward C. answered 02/28/15
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Caltech Grad for math tutoring: Algebra through Calculus
v0 = initial velocity = 100 ft/s
S0 = initial height = 0 since it was thrown from the ground
The formula for height above the ground t seconds after being thrown is
s = -16t2 + 100t
To find when the duckie will be 50 ft above the ground, set s = 50 and solve for t
50 = -16t2 + 100t
16t2 -100t + 50 = 0
8t2 - 50t + 25 = 0
This doesn't factor so use the quadratic equation
t = [50 +/- sqrt(2500 - 4(8)(25))] / 16
t = [50 +/- sqrt(1700)] / 16
t = [50 +/- sqrt(4*25*17)] / 16
t = [50 +/- 10sqrt(17)] / 16
t = [25 +/- 5sqrt(17)] / 8
t ~ 5.702 or t ~ 0.548 seconds
To find when it returns to the ground set s = 0 and solve for t
0 = -16t2 + 100t
4t2 - 25t = 0
t(4t - 25) = 0
t = 0 or t = 25/4 = 6.25 seconds
It was thrown at t = 0 so it will return to the ground at t = 6.25 seconds