Chemistry hw Help

Question

A 180mL of a gas occupied 302K at 0.atm. What would be the new temperature if the gas volume changed at 90mL at a final pressure of 3.20atm?

Answer 1

The best way to set this question up is using the Combined Gas Law

P1*V1 / T1 = P2*V2 / T2

In this question what you’re solving for is the new temperature (T2) so you can just solve that equation algebraically for T2 and then plug in the values for the other variables based on the information that we know

T2 = (P2*V2*T1) / (P1 * V1)

T2 = (3.20 atm * 90 mL * 302 K) / (0.5 atm * 180 mL)

T2 = 87000 / 90

T2 = 966.4 K

The 966.4 K would be the temperature under the new conditions